A solution of CCl4 has a molality of 1.35 m. The freezing point depression constant
for CCl4 is 30 oC x kg/mol and its freezing point is -22.99 oC. What would its new
freezing point become?

sosoos would you like multiply 1.35m with 30C then take the number and subtract it from -22? or add....

Question

A solution of CCl4 has a molality of 1.35 m.  The freezing point depression constant 
    for CCl4 is 30 oC x kg/mol and its freezing point is -22.99 oC.  What would its new 
    freezing point become?

sosoos would you like multiply 1.35m with 30C then take the number and subtract it from -22? or add....

anonymous · Answer

oC is celsius

wolfe8 · Answer

It looks kinda weird because what is the change that causes a change in freeing point? Maybe I'm just over thinking it. I would say subtract? Not sure. Good luck.

aaronq · Answer

you would subtract it because it's a depression in freezing point ("depression" meaning "lowering") so the new FP would be more negative than that of the pure solvent.