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Linear Algebra 19 Online
OpenStudy (anonymous):

Medal! <3 Emily uses her college photocopier machine to photocopy at the rate of $0.08 per page. She decides to rent a photocopier machine for $90 a year. The cost of photocopying using the rented machine is $0.03 per page. Part A: Write an inequality that can be used to calculate the number of pages that Emily should photocopy in a year so that the amount she pays for the rented machine is less than the college machine. Define the variable used. (5 points) Part B: How many pages should Emily print in a year to justify renting the photocopier? Show your work. (5 points)

OpenStudy (anonymous):

@Lethal can you help?

OpenStudy (anonymous):

@tkhunny can you help me please?

OpenStudy (tkhunny):

Please NAME the number of pages per year. Seriously, just give it a name.

OpenStudy (anonymous):

copy paper?

OpenStudy (tkhunny):

She uses some number of pages, right?

OpenStudy (anonymous):

yes...

OpenStudy (tkhunny):

Shall we refer to that number of pages as "the number of pages she uses" or shall we invent a more convenient name, so we can talk about it?

OpenStudy (anonymous):

P for pages

OpenStudy (tkhunny):

Very good. That is exactly what is needed. Can you now write an expression for the total cost of copies, given P pages, and using the college photocopier?

OpenStudy (anonymous):

90p+0.8?

OpenStudy (tkhunny):

?? I sincerely hope not. That is VERY expensive. We don't use the $90 until we rent. Let's ignore that for now. Just consider the cost of using the college copier. Remember to multiply P but eh cost per page. Also, just for future reference, it is usually considered poor notation to switch from P to p. They are generally NOT considered the same. Just pick one and stick with it! :-)

OpenStudy (anonymous):

p is fine :)

OpenStudy (tkhunny):

Okay, can you now write an expression for the total cost of copies, given p pages, and using the college photocopier? It's NOT the rented one, so do not use the $90.

OpenStudy (anonymous):

sorry i am terrible at math. 0.08p+0.03???

OpenStudy (tkhunny):

So far, your math seems fine. Your organization seems a little off. College Copier .08/page Nothing to do with $90 Nothing to do with 0.03/page The cost for all the pages, using the college copier is "0.08p". We're ONLY talking about the one copier. You keep trying to throw in the other copier. Keep them separate and organized. Rented Copier. Nothing to do with 0.08/copy. The cost for all the pages, using the rented copier is "90 + 0.03p". This needs to make sense.

OpenStudy (anonymous):

Ok still a little confused.... :/

OpenStudy (tkhunny):

For greater understanding, simply ignore one case or the other. (Just long enough to understand. I promise, we'll get back to it, later.) I ask, how much will it cost to run the college copier for a year. You say, 0.08p. Done. I ask, how much will it cost to run the rented copier for a year. You say, 90.00 + 0.03p. Done.

OpenStudy (anonymous):

Ok

OpenStudy (tkhunny):

Now, we are ready to answer Part B. Rephrased, what number of pages, or what value of p, will make these two expressions have the same value? Can you answer it?

OpenStudy (anonymous):

wouldn't you have to subtract or multiply?

OpenStudy (tkhunny):

Let the notation help you. We went to teh trouble to write those two expression for a reason. IF we are indifferent to the two options, the cost would be the same. In the language of our algebra, that is this: 0.08p = 90.00 + 0.03p 1) Do you see that this is so? 2) Can you solve it? We need a nice value for p.

OpenStudy (anonymous):

No i cant solve it i am totally lost.

OpenStudy (anonymous):

@Taylor<3sRin can you help me please?

OpenStudy (anonymous):

nevermind i got it. it equals 1800.

OpenStudy (anonymous):

this is on FLVS Maybe you would pass algebra finally if you stopped cheating and learned the material

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