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Mathematics 23 Online
OpenStudy (usukidoll):

Let P(x) denote the statement "x less than or equal to 4." What are the truth values? a) P(O) b) P(4) c) P(6)

OpenStudy (usukidoll):

so I would put that there are some values of x that satisfy P(x) due to the fact that P(0) makes 0 < or = to 4 P(4) just makes everything equal P(6) is well x is greater than or equal to 4 so that's not right so backwards E x P(x)

OpenStudy (usukidoll):

ouch no wait there's a less than or equal to sign so P(4) will work. for P(0) and P(4) backwards E [x]P(x) which stands for some values of x in P(x) P(6) is false

OpenStudy (usukidoll):

Let P(x) be the statement "the word x contains the letter a." What are the truth values? a) P(orange) b) P(lemon) c) P(true) d) P(false)

OpenStudy (usukidoll):

obviously A and D have the letter a. so again it's for some values of x in P(x) because A is true, B is false, C is false, and D is true. Therefore, backwardsE[x]P(x)

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