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Chemistry 16 Online
OpenStudy (anonymous):

can someone help with this question?

OpenStudy (anonymous):

OpenStudy (doc.brown):

Is M the molarity?

OpenStudy (anonymous):

yeah

OpenStudy (aaronq):

since the half-life is dependent on the concentration it's a second order reaction

OpenStudy (aaronq):

oh wait it can be a zeroth reaction as well

OpenStudy (anonymous):

2ed is right

OpenStudy (aaronq):

okay, use the half life formula: t1/2 = 1 / k [Ao]

OpenStudy (aaronq):

for the 2nd part

OpenStudy (anonymous):

can u help with another question

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

sure post it

OpenStudy (anonymous):

OpenStudy (aaronq):

instead of [C], it should be [D]. C is a product, not a reactant

OpenStudy (anonymous):

so (a)(d)

OpenStudy (anonymous):

it says its wrong

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

hm maybe try using the slow step only? so rate=k[B][D]

OpenStudy (anonymous):

it says this You are on the right track, but your answer includes an intermediate that is not present in the overall reaction. Use the equilibrium step to find a substitute expression for that intermediate in the rate law.

OpenStudy (anonymous):

so idk

OpenStudy (aaronq):

did it say that when you put [A]^2[D] or [B][D]?

OpenStudy (aaronq):

the formation of [B] is dependent on[A]^2 so d[B]/dt=-d[A]^2/dt

OpenStudy (anonymous):

[B][D]

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