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OpenStudy (anonymous):
OpenStudy (doc.brown):
Is M the molarity?
OpenStudy (anonymous):
yeah
OpenStudy (aaronq):
since the half-life is dependent on the concentration it's a second order reaction
OpenStudy (aaronq):
oh wait it can be a zeroth reaction as well
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OpenStudy (anonymous):
2ed is right
OpenStudy (aaronq):
okay, use the half life formula: t1/2 = 1 / k [Ao]
OpenStudy (aaronq):
for the 2nd part
OpenStudy (anonymous):
can u help with another question
OpenStudy (anonymous):
@aaronq
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OpenStudy (aaronq):
sure post it
OpenStudy (anonymous):
OpenStudy (aaronq):
instead of [C], it should be [D]. C is a product, not a reactant
OpenStudy (anonymous):
so (a)(d)
OpenStudy (anonymous):
it says its wrong
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OpenStudy (anonymous):
@aaronq
OpenStudy (aaronq):
hm maybe try using the slow step only?
so rate=k[B][D]
OpenStudy (anonymous):
it says this You are on the right track, but your answer includes an intermediate that is not present in the overall reaction. Use the equilibrium step to find a substitute expression for that intermediate in the rate law.
OpenStudy (anonymous):
so idk
OpenStudy (aaronq):
did it say that when you put [A]^2[D] or [B][D]?
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OpenStudy (aaronq):
the formation of [B] is dependent on[A]^2
so d[B]/dt=-d[A]^2/dt