Question

How to solve this? Calculus II problem... Area under a curve. (symmetry)

Answer 1

#47
btw

Answer 2

I already know that the integral for the interval [-2,0] is negative. And i developed an anti derivative of

Answer 3

(2/3)(4-x^2)^(3/2)

Answer 4

You don't need to solve the area on the left.. you can see it's symmetric.. means it's 0.

Answer 5

Okay.

Answer 6

In addition.. the function is odd.. so the integral = 0 between [-a,a]

Answer 7

have to prove it is odd and then apply the theorem to get 0

Answer 8

for the second one ,just distribute sin into the bracket and take integral term by term