Question

I'm given a problem on my exam review that I don't remember how to solve?

I have to find the values for x and y that make this true:
http://puu.sh/6AmQU.png

Can anyone help me solve this?

Answer 1

solve the system
\[2y+5=x-1\\
y-2=3x\]

Answer 2

2y + 6 = x, (y-2)/3 = x?

Answer 3

first equation is the same as
\(2y+6=x\) substitute it in to the second equation and get
\[y-2=3(2y+6)\]

Answer 4

solve that one for \(y\) then substitute back and solve for \(x\)

Answer 5

Ahhhh that's right. Now it's starting to look familiar. Gimmie a second to solve that

Answer 6

\[y-2=3(2y+6)\\
y-2=6y+18\\
-20=5y\\
-5=y\]

Answer 7

I got y = -4 for some reason

Answer 8

You added 18 to positive 2 instead of negative, your -20 should have been 16

Answer 9

y = -4 checks out because when it's plugged in, x = -2 in both equations