CAN YOU PLEASE HELP? The length of a rectangle is (6x2 + 3x - 2) units, and its width is (x3 - 2x + 5) units. Part A: What is the area of the rectangle? Show your work. (5 points) Part B: Does the answer for Part A show that polynomials are closed under an operation? Justify your answer. (3 points) Part C: What is the degree and classification of the expression obtained in Part A? (2 points)
Area = length * width = (6x^2 + 3x - 2) * (x^3 - 2x + 5) Multiply it out and simplify.
is that for part a?
Yes. Take the first term 6x^2 and multiply each of the term x^3, -2x & 5. Then take 3x and multiply each of the term x^3, -2x & 5. Do the same with -2. Then add like terms and simplify.
What is 6x^2 * x^3 ?
6x5?
Yes. 6x^5. Now do the same with the rest of the terms. Distribute the terms.
(6x^2 + 3x - 2) * (x^3 - 2x + 5) = 6x^2 * x^3 + 6x^2 * (-2x) + 6x^2 * 5 + 3x * x^3 + 3x * (-2x) + 3x * 5 - 2 * x^3 - 2 * (-2x) - 2 * 5 = ?
(6x2+3x−2)(x3−2x+5)?
wait that's wrong..
That is what we started with. We need to multiply those two expressions. So you need to distribute them. And I have shown in my previous reply how to distribute them.
when multiplying i got 6x5+3x4−14x3+24x2+19x−10
Good job!!!
thanks!. could you please help with part b and c?
Part b) In part a) we multiplied two polynomials with integer coefficients and the results was 6x^5+3x^4−14x^3+24x^2+19x−10 which is also a polynomial with integer coefficients. Therefore, the multiplication of two polynomials results in a polynomial and therefore polynomials are closed under multiplication.
thanks your a saint
also if you could lead me to the right direction on point c?
part c) The degree of a polynomial is the highest degree of its variable. The degree of the result obtained in part a is five. This is a fifth degree polynomial. Sometimes it is also called a quintic polynomial (meaning fifth degree).
thanks !!!!!! so much i really appreciate it
I don't really understand part c.
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