Question

What is the equation of the line that passes through the points (2, –1) and (6, 1)?

Answer 1

First, find the graient of the line..do you know how to find it?

Answer 2

gradient*

Answer 3

no

Answer 4

The gradient is found by using this formula: y2-y1/x2-x1 where x and y are the coordinates. So, the gradient will be: (1--1)/(6-2) and we end up with 2/4 which can be simplified to 1/2

Answer 5

Then, inorder to find the equation of the line, we use the formula y-mx+c, where y is y-coordinate, m is the gradient/slope of the line, x is the x-coordinate and c is the y-intercept (the place where the line cuts the y-axis). So, let's say we use the coordinates (6,1), substituting, we get: 1=1/2(6)+c. We have to solve for c, so we get 1=3+c. c=1-3 = -2. Thus, the equation of the line is y=1/2x-3

Answer 6

so its y=-2x-3 or y=-1/2x-1

Answer 7

if this is a straight line, use y=mx+b. first find the slope:
m=y2-y1/x2-x1
=1+1/6-2
=2/4
slope=1/2
now plug in any point with the slope to find b
y=mx+b
(1)=(1/2)(6)+b
1=6/2+b
1=3+b
-2=b
so equation is: (y=mx+b)
y=1/2 x -2