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A box has a volume of x^3 - 16x cm^3. Another box has a volume of x^3 - 4x^2 cm^3. What is the ratio of the volume of the first box to that of the second? So I divide, right? x^3 - 16 / x^3 - 4x^2 ? But then I'm stuck...
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* x^3 - 16x / x^3 - 4x^2
You need to factor like so..
ok... so \[\frac{ x(x^2- 16) }{ x^2(x -4) }\] \[\frac{ x(x+4)(x-4) }{ x^2(x-4) }\] am I on the right track?
Yes you are.
what do I do next?
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Find any common factors?
(x-4)?
Yes, and one more.
x?
Excellent!
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so if I take out the common factors... \[\frac{ x + 4 }{ x }\] is that my answer?
Yep.
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