Question

Show that there is a number c, with 0 ≤ c ≤ 1, such that f(c)=0.

f(x)= 7^x - 6/x

**answer choices attached inside..

please explain! thanks :)

Answer 1

A,B,C,D,E from top to bottom :)

Answer 2

This is... the intermediate value theorem?

Answer 3

all but the lone x in the numerator?

Answer 4

yeah

it's first 7^x by itself.. then - (6/x)

Answer 5

sorry that wasn't really clear! i can't use the draw tool :(

Answer 6

Good lord what a clusterf*ck of answer choices :/ seems like they made it as annoyingly long and confusing as possible.

It'll be one of the answer choices that shows f is below zero, then greater than zero... (y has to go from negative to positive for there to be an x-intercept)

Answer 7

haha i know :P

Answer 8

hate it when there are so many choices :/ and long ones too :/

Answer 9

Last answer is bollocks. Where did 600 come from. Eliminate the stupid choices.

Answer 10

haha okie :)

Answer 11

so it can only be either C or D right?

Answer 12

Eliminate all choices where they have f(0) since 6/0 is undef.

Answer 13

okay so that only leaves choice D right?

Answer 14

Yep, all the other choices are stupid and/or dumb.

Answer 15

okay awesome! thanks :)

Answer 16

Wow that second answer choice got a triple dose of stupid. They're both < 0. And the random 600, the f(1) being -5... IN WHAT UNIVERSE IS SEVEN MINUS SIX EQUAL TO NEGATIVE FIVE?!?! I am pretty sure that if i have seven apples, and give away six, that I'll have one apple left, not negative five apples left.

Answer 17

lol yeah it's really weird... i'll have to ask my teacher about that hahaha

Answer 18

not sure where these worksheets come from lawlzz

Answer 19

:D