Question

Find the largest three digit integer that is divisible by each of its distinct non zero digits.

Answer 1

distinct digits

Answer 2

"its distinct non zero digits" so i presume the digits must be different

Answer 3

but i cant think of a way other than trial-n-error....

Answer 4

Yeah trial and error is all I can think of too.

Answer 5

But I bet there is a trick to it.

Answer 6

im putting 984 up n see if anyone beats that! lol

Answer 7

No I think you're right

Answer 8

Wait nope
not divisible by 9

Answer 9

superdavesuper, I was thinking the same thing too. I know that 936 is divisible by 3, 6 and 9, so I was planning on working my way down to from 999 to 936. 984 isn't divisible by 9, so that won't work.

Answer 10

AH crap....forgot the 9.....hahaha have fun guys! ;)

Answer 11

Thanks. My initial instinct was trial and error, but I was hoping to find a quicker way to solve it. I will just plug away for a while.

Answer 12

Well you can work through intervals of nine which will make it go faster.

Answer 13

I.e. 981 is divisible by 9 but not by 8 so next try 972 and so on

Answer 14

936 is it

Answer 15

Still think there's gotta be an easier way.

Answer 16

well there is....the 2 largest digits are 9 n 8....so 9x8=72....divide 999 by 72 u get 13.xxx so 13x72=936 :)

i just thought of this! lol

Answer 17

Thanks everyone

Answer 18

HA! way to think outside the box @superdavesuper

Answer 19

hummm its kind of
to find the larget
u might find infinite num im sure :|

Answer 20

u found 936
but this num is larger

936150

Answer 21

Largest 3-digit dude.

Answer 22

ohhhh sry i dint note 3 digit lol
i was totally confused huh