A mixture placed in an Erlenmeyer flask comprises of 6ml of silica gel and 40ml of solvent containing, in solution, 100mg of a non-volatile compound. After stirring, the mixture was left to stand before a 10ml aliquot of the solution was extracted and evaporated to dryness. The residue weighed 12mg. Calculate the adsorption coefficient K=C(stationary phase)/C (mobile phase) of the compound in this experiment.
do you understand what's going on?
Not really for this question. For the other chromatography question I can solve them using the equations given and relationships between them, but this one I have no clue.
so you had 100 mg of a compound, 40 mL of solvent and 16 mL of gel. now, you mixed it and sampled a 10 mL portion of the solvent and found 12 mg of the compound. 10 mL is i quarter of the 40 mL total, so 12 mg*4= 48 mg of the solute is in the solvent, (100-48mg)=52 mg is adsorbed to the gel. can you finish it now?
okay say 52mg is adsorbed into the gel what is the relationship between the math you did and the equation shown above?
adsorption coefficient, K=C(stationary phase)/C (mobile phase) C = concentration stationary phase = gel mobile phase = solvent
concentration = mol/vol i cant get mol
concentration can be anything, you obviously can't use moles, use mg/mL
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