Limis as x approaches negative infinity of : x/e^x= - infinity why ?
because the limit \(x\to -\infty\) of \(e^x\) is \(0\) through positive numbers
but then we get x/0
\(\frac{x}{0}\) is not a number
oh i get it
\(e^x\) gets smaller and smaller, by which i mean it gets closer and closer to zero, but of course is never actually equal to zero imagine it was \(0.001\) \(x\) is going to \(-\infty\) and so imagine it is \(-10000\)
we get -infinity/1
no, not one in the denominator, a very very small positive number in the denomiator
yeah looking at the graph makes it more clear thanks
trying it with say \(x=-100\) would give you a good idea too, and \(-100\) is a small step on the way to \(-\infty\)
right not one but a positive small number great
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