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Mathematics 22 Online
OpenStudy (anonymous):

what is the solution if possible

OpenStudy (destinymasha):

?

OpenStudy (anonymous):

OpenStudy (anonymous):

sorry i forgot that

OpenStudy (triciaal):

isolate the radical move everything else to the other side of the = and keep the balance

OpenStudy (anonymous):

wait so what do i do with the three in front of the sqrt

OpenStudy (triciaal):

divide to make it 1

OpenStudy (triciaal):

you can express 8 as 2^3 and the fifth root is the same as power 1/5

OpenStudy (anonymous):

^5sqrt((x+2)^3)=10 this is what i have so far

OpenStudy (triciaal):

do you have (x +2)^3/5 = 2^3

OpenStudy (anonymous):

how did you get that

OpenStudy (triciaal):

start at the top show me your work

OpenStudy (anonymous):

oh wait nevermind i see okay i forgot that the 5 root goes in the denominator

OpenStudy (triciaal):

what is (27 -3) / 3 ?

OpenStudy (anonymous):

8?

OpenStudy (triciaal):

8 can be written as 2^3

OpenStudy (anonymous):

oh yea okay i got it

OpenStudy (anonymous):

so is this my answer (x+2)^3/5=2^3

OpenStudy (triciaal):

no we need to find x lets continue

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

does this (x+2)^3/5 get simplified

OpenStudy (triciaal):

think about rules for exponents

OpenStudy (anonymous):

do you distribute the 3/5 to x and 2

OpenStudy (triciaal):

we want the power of (x +2) to be 1 so we multiply by 3/5 by 5/3 and do the same to the other side (working with eqn)

OpenStudy (triciaal):

no the 3/5 is the power to which the whole expression (x + 2 ) is raised

OpenStudy (anonymous):

(x+2)=40/3 is that what you get if you multiply 5/3 to both sides

OpenStudy (anonymous):

i did 8(5/3) on the other side

OpenStudy (triciaal):

(x + 2)^(3/5)(5/3) = 2^(3)(5/3)

OpenStudy (triciaal):

working with the exponents

OpenStudy (triciaal):

(x +2) ^1 = 2^5 x + 2 =32 x =30

OpenStudy (anonymous):

(x+2)=2^5 so now this?

OpenStudy (anonymous):

thank you so mcuh

OpenStudy (triciaal):

yes

OpenStudy (triciaal):

great rule of practice check your ans

OpenStudy (triciaal):

good job!

OpenStudy (anonymous):

could you help me with a last one

OpenStudy (anonymous):

please

OpenStudy (triciaal):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

simplest form of the radical expression

OpenStudy (triciaal):

great this won't take long you are adding like terms

OpenStudy (anonymous):

okay do i add 6 and 3 first

OpenStudy (triciaal):

you have 3(2a)^(1/3)-6(2a)^(1/3)

OpenStudy (anonymous):

s0 is it 9 (4a)^1/3

OpenStudy (triciaal):

no look at it for a minute

OpenStudy (triciaal):

pretend 2a^1/3 is c then it would be 3c - 6c

OpenStudy (anonymous):

so just 9(2a)^1/3?

OpenStudy (triciaal):

watch your signs

OpenStudy (anonymous):

oh -3(2a)^1/3

OpenStudy (triciaal):

you got it! keep practicing and it will come very easy. good job

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