Mathematics
22 Online
OpenStudy (anonymous):
what is the solution if possible
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OpenStudy (destinymasha):
?
OpenStudy (anonymous):
OpenStudy (anonymous):
sorry i forgot that
OpenStudy (triciaal):
isolate the radical move everything else to the other side of the = and keep the balance
OpenStudy (anonymous):
wait so what do i do with the three in front of the sqrt
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OpenStudy (triciaal):
divide to make it 1
OpenStudy (triciaal):
you can express 8 as 2^3 and the fifth root is the same as power 1/5
OpenStudy (anonymous):
^5sqrt((x+2)^3)=10 this is what i have so far
OpenStudy (triciaal):
do you have (x +2)^3/5 = 2^3
OpenStudy (anonymous):
how did you get that
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OpenStudy (triciaal):
start at the top show me your work
OpenStudy (anonymous):
oh wait nevermind i see okay i forgot that the 5 root goes in the denominator
OpenStudy (triciaal):
what is (27 -3) / 3 ?
OpenStudy (anonymous):
8?
OpenStudy (triciaal):
8 can be written as 2^3
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OpenStudy (anonymous):
oh yea okay i got it
OpenStudy (anonymous):
so is this my answer
(x+2)^3/5=2^3
OpenStudy (triciaal):
no we need to find x lets continue
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
does this (x+2)^3/5 get simplified
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OpenStudy (triciaal):
think about rules for exponents
OpenStudy (anonymous):
do you distribute the 3/5 to x and 2
OpenStudy (triciaal):
we want the power of (x +2) to be 1 so we multiply by 3/5 by 5/3 and do the same to the other side (working with eqn)
OpenStudy (triciaal):
no the 3/5 is the power to which the whole expression (x + 2 ) is raised
OpenStudy (anonymous):
(x+2)=40/3 is that what you get if you multiply 5/3 to both sides
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OpenStudy (anonymous):
i did 8(5/3) on the other side
OpenStudy (triciaal):
(x + 2)^(3/5)(5/3) = 2^(3)(5/3)
OpenStudy (triciaal):
working with the exponents
OpenStudy (triciaal):
(x +2) ^1 = 2^5
x + 2 =32
x =30
OpenStudy (anonymous):
(x+2)=2^5 so now this?
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OpenStudy (anonymous):
thank you so mcuh
OpenStudy (triciaal):
yes
OpenStudy (triciaal):
great rule of practice check your ans
OpenStudy (triciaal):
good job!
OpenStudy (anonymous):
could you help me with a last one
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OpenStudy (anonymous):
please
OpenStudy (triciaal):
ok
OpenStudy (anonymous):
OpenStudy (anonymous):
simplest form of the radical expression
OpenStudy (triciaal):
great this won't take long
you are adding like terms
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OpenStudy (anonymous):
okay do i add 6 and 3 first
OpenStudy (triciaal):
you have 3(2a)^(1/3)-6(2a)^(1/3)
OpenStudy (anonymous):
s0 is it 9 (4a)^1/3
OpenStudy (triciaal):
no look at it for a minute
OpenStudy (triciaal):
pretend 2a^1/3 is c
then it would be 3c - 6c
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OpenStudy (anonymous):
so just 9(2a)^1/3?
OpenStudy (triciaal):
watch your signs
OpenStudy (anonymous):
oh -3(2a)^1/3
OpenStudy (triciaal):
you got it! keep practicing and it will come very easy. good job