Question

Find the constant of variation for the quadratic variation.

6y = 9x2

a. 4/9
b. 2/3
c. 3/2
d. -2

Answer 1

Any ideas?

Answer 2

$$\Huge 6y = 9x^2 $$

Answer 3

3/2?

Answer 4

A "quadratic" variation has the form $$\Huge y = kx^2 $$

Answer 5

$$\Huge 1y = kx^2 $$

Answer 6

But your question has a numerical coefficient of 6 in front of the y...so ..

Answer 7

$$\Huge 6y = 9x^2 $$
$$\Huge \frac{1}{6}*6y = \frac{1}{6}*9x^2 $$
$$\Huge \frac{1}{\cancel 6}*\cancel 6y = \frac{1}{6}*9x^2 $$
$$\Huge y = \frac{1}{6}*9x^2 $$