please help!! The concentration of sodium hydroxide is 1.0 M and the concentration of crystal violet is 1.00E-5 M. identify the limiting reagent and calculate how much of the excess reagent remains after the reaction runs to completion.
this is all I'm given. how do i find the balanced equation?
You can look those compounds up for the formulas. Then you can look at the ions and write the products yourself.
is this right? found it on google C25N3H30Cl + NaOH = C25N3H30OH + Na + Cl
Looks right to me. But wouldn't the Na and Cl combine?
yea, so C25N3H30Cl + NaOH = C25N3H30OH + NaCl. now how do I find the limiting reagent since its in Molarity. usually I do it when its in grams
Use the formula n=mV where n is the number of moles, m the molarity and V is volume.
so I have mol and M and I find V? and then I do volume=g/mol?
No you need n, number of moles to find the limiting reagent. Are you given the volume?
ooh, no I am not
Hmm then I think we will assume we have 1L of each solution. Have you balanced the equation?
ok, I believe it is balanced
So since we know the ratio is 1:1:1:1, and crystal violet is less than NaOH, crystal violet will be the limiting reagent. Because it will run out first and the reaction will have to stop.
aha! yea thats right. why didnt i think of that. -_-
Yup and NaOH is called the reagent in excess. Can you do it from here?
well now how do we calculate how much of the excess remains?
Well, you will use the violet and NaOH at the same rate since the ratio is 1:1. So when all 1.00E-5 moles of the violet is used up, the same amount of NaOH is used up. So can you find the excess?
so 1-1.00e-5?
Yup. :)
that wasn't too bad. But thanks anyway!! :)
You're welcome. Also, if the ratios are not 1:1, then you will have to divide the number of moles with their respective coefficients.
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