Question

Need help with integral!! someone !!

Answer 1

Its the v) one

Answer 2

Type it with equation editor or post a clearer pic

Answer 3

\(\Large \int \dfrac{\sec \theta \tan \theta d\theta }{(4+\sec \theta)^2} \)

Answer 4

dd you try u = 4 + sec theta ?

Answer 5

\[\int\limits_{?}^{?}\ \frac{ \sec \theta \tan \theta }{(4+\sec \theta)^2}\]

Answer 6

and yes but I got + instead of - in my answer....

Answer 7

tg is tangent...?? Since when...

Answer 8

Don't know.. I think its weird too but it's my book so :s

Answer 9

integral of x^(-2) dx will be -1/x +c
thats where - *minus* comes from

Answer 10

I dont understand... :/

Answer 11

then show your work, how did you get that '+'

Answer 12

I have all the good answer but I dont have the ''-''

Answer 13

did u get
\(\Large \int \dfrac{1}{u^2}du\)

Answer 14

yes I have this!!

Answer 15

that = \(\dfrac{-1}{u}+c\)

Answer 16

right ?

Answer 17

\(\int x^n dx = \dfrac{x^{n+1}}{n+1}+c\)
\(\int x^{-2} dx = \dfrac{x^{-2+1}}{-2+1}+c = \dfrac{-1}{x}+c\)

Answer 18

ohhhhh I see

Answer 19

I understand now!!

Answer 20

thank you :)))

Answer 21

welcome ^_^