Question

If sec(theta)=5/3 and the terminal point determined by theta is in quadrant 4, then: (check all correct)
sin(theta)=-2/5
cos(theta)=3/5
csc(theta)=-5/4
tan(theta)=4/3

Answer 1

@ranga can you help

Answer 2

Remember in 4th quadrant only cos theta and sec theta are positive all other T-ratios are negative.

Answer 3

Write -4K in place of 4k in the diagram.
\[\csc \theta=\frac{ BA }{AC }=\frac{ 5K }{-4K }=-\frac{ 5 }{4 }\]
\[\tan \theta=\frac{ AC }{BC }=\frac{ -4K }{3K }=-\frac{ 4 }{3 }\]