Question

∫(sinx)^3 dx

Answer 1

i believe the answer is (1/3)(cosx)^3 -x but I want to be sure

Answer 2

Lets rewrite it..
sin^3(x)=(−cos^2(x)+1)sin(x)

Answer 3

=−sin(x)cos^2(x)+sin(x)

Answer 4

i got to the point where it was (1-(cosx)^2)sins dx

Answer 5

then you use u-sub

Answer 6

yes

Answer 7

but your final answer is a bit wrong i think

Answer 8

so the next step would be -∫1-u^2 du right? after the u-sub

Answer 9

(1/3)(cosx)^3 is integral of −sin(x)cos^2(x)

Answer 10

yes

Answer 11

Then just add integral of sin(x to that...

Answer 12

ok