An airplane travels 600 miles against the wind in 4 hours, and makes the return trip with the same wind in 2 hours. Find the rate
I love these problems :-) Okay, the plane flying with the wind goes at a speed of \(s+w\) over the ground, where \(s\) is the speed of the plane without any wind, and \(w\) is the speed of the wind. The plane flying against the wind goes at a speed of \(s-w\) over the ground. Using the distance formula \(d = s * t\) where \(d\) is distance, \(s\) is speed, and \(t\) is time, we have two equations: \[600 = (s-w)*4\text{ (flying against the wind)}\]\[600 = (s+w)*2\text{ (flying with the wind)}\] Do you know how to solve that system of equations?
will I add s and w together?
Distribute the stuff on the right hand sides first. What do you get for the two equations?
\[600 = 4s - 4w\]\[600=2s+2w\]
6s-2w=600
Uh, no, that isn't what we want. We need to multiply one or both of the equations by numbers that will make one of the columns of coefficients have equal values with opposite signs, perhaps \(-4w\) and \(4w\). Then when we add the two equations together, that variable will vanish and we'll have a new equation in only one variable to solve.
What happens if you multiply the second equation by 2?
\[600=4s-4w\]\[2*600 = 2*2s + 2*2w\] \[600=4s-4w\]\[1200=4s+4w\]----------------- \[600+1200= 4s+4s -4w + 4w\]\[1800=8s+0w\]\[s=\]
From the value you get for \(s\), you can find \(w\) by plugging the value of \(s\) into either of the equations and solving for \(w\).
divide 1800 by 8? Cancel out the 0
so the value of \(s\) is?
Hey, you're not done yet. You need to find the value of \(w\), then check your work by plugging the values you found for \(s\) and \(w\) into both equations to make sure that both are satisfied.
Join our real-time social learning platform and learn together with your friends!