Question

Find the nth derivative of g(x)

Answer 1

\[\LARGE g(x)=\frac{1}{x}\]

Answer 2

\[\frac{(-1)^n n!}{x^{n+1}}\]

Answer 3

Hmm, +1?

Answer 4

y = 1/x
y' = -1/x^2
y'' = 2/x^3
y''' = -3*2/x^4
...
y^(n) = (-1)^n n!/x^(n+1), where n starts from 1