A helicopter is ascending vertically with a speed of 1.00 m/s. At a height of 75 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground? [Hint: The package's initial speed equals the helicopter's.]

Question

anonymous · Answer

when the package is dropped, it keep raise up for a while. Because of its initial velocity is 1 m/s  , you can calculate very easily the time that need to the package' velocity become zero. 

V(final)=V(initial)-g*t 

then you should calculate the maximum height for finding the time that need  for free falling. 

X=V(initial)*t + (gt^2)/2

anonymous · Answer

Okay, so just to make sure...is 1 m/s v final or v initial? X also equals the height, i'm guessing and g is acceleration, so -9.8m/s^2

Am I right so far?