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OpenStudy (nincompoop):
how would you solve this?
OpenStudy (tester97):
factor it out first which i did and got \[\frac{ n^{2}-6 }{ n ^{2}-2 }\] but i want to know how would i find the restrictions
OpenStudy (anonymous):
\[\frac{ }{ (n^2 - 5)(n^2 - 2) }\]
when either of these equals zero, the denominator is zero
OpenStudy (tester97):
Ok so what do i do? im sorry im not very good in math.
OpenStudy (bibby):
When does a product equal 0?
a*b
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OpenStudy (tester97):
Oh god im so dumb /.\ the answer was in front of me the whole time. Just add the 2 and you would have n^2=2 then square root it and you have √2 would that be right?
OpenStudy (bibby):
Set it equal to 0 first, but yeah
OpenStudy (tester97):
and do the same for (n^2-5) right?
OpenStudy (bibby):
yeah. and when you take the square root of 5, remember that you add the plus minus sign because:\[(-5)^2 = 25 = (5)^2\]
OpenStudy (tester97):
\(\Large\color{orange}{Thanks~Aviv~♥}\)
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