when finding the positive acute angle of an angle that lies in quadrant 3, do you subtract thetha from 180?
*180 from thetha
Em I am not really sure about this one can you help
can i give you the problem
sure thing
cos 230 as a positive acute angle?
i think its actually - cos50 but idk how to do the work
I dont remember well but there was a principle cos(-a) = cos(a)
erm ... the angle 230 makes with the x axis would be 50 degrees because 230-180 = 50 then the "All Students Take Calculus" thing https://en.wikipedia.org/wiki/All_Students_Take_Calculus so you know cos is negative in Quadrant 3
so yeah naruto is right :)
omg Em you are intelligent ^_^
LOL thanks xDD!! but urmm idk how to do tan(-45) ):
tan(-45) = tan(360-45) = tan(315) and 315 is just 45 under the x axis (quadrant 4) tan is negative in Q4 so so -tan(45) .... which can be figured out with a 45 45 90 triangle
wait.... i don't get it.....
i cant even figure out the answer.. isnt it supposed to be acute?
sorry >.< annas asked me to help, but I'm just a bit tired XD |dw:1391891814553:dw|so tan(45) = 1 tan(-45) is in quadrant 4 so tan(-45) = -1
i realize that so wont the answer be similar like - tan 45... can that even be right?/
yeah tan(-45) = -tan(45) because tan(-45) = tan(315) = -tan(45)
but can it be the same? is that right... i mean its basically the same thing..
mmm yeah :) but but I'm not sure if it always works like that, so be careful
thanks so much ! i hate take home tests -_-
LOL I always seem to mess them up some how XD
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