Question

simplify [ (3x^(3/2)Y^3)/(x^2y^-1/2) ]^2

Answer 1

\[[\frac{ 3*x^{3/2} *y^3}{ (x^{2}*y^{-1/2}) }]^{2}\]

Answer 2

sorry its all to the -2

Answer 3

\[[3*x^{\frac{ 3 }{ 2 }-2}*y^{3-\frac{ (-1) }{ 2 }}]^{-2}\]

Answer 4

\[3x \frac{3y^{3} }{2 } {-4} y\]

Answer 5

\[[3*x^{\frac{ -1 }{ 2 }}*y^{\frac{ 7 }{ 2 }}]^{-2}\]

Answer 6

\[3^{-2}*x^{(\frac{ -1 }{ 2 }*(-2))}*y^{(\frac{ 7 }{ 2 }*(-2))}=\frac{ 1 }{ 9 }*x^{1}*y^{-7}\]

Answer 7

\[\frac{ x }{ 9*y ^{7} }\]
@Ssusu

Answer 8

thank uu @gorv

Answer 9

\[3x \frac{ 11 }{ 2 }y2\]

Answer 10

@Ssusu always welcme :)