What is the derivative of f(x)=x^(2/3) ?
Just follow the power rule\[\frac{ d }{ dx}x^2 = nx^{n-1}\]
i haven't learned the power rule yet, only the difference quotient
This is what the power rule looks like\[\large \frac{ d }{ dx}x^n = nx^{n-1}\]
how do you use it?
for example x^3 = 3x^(3-1) = 3x^2
@bibby, you mean d/dx (x^n), right ?
lol yeah, fixed that up in the second post
then would it be 2/3x^(-1/3) ?
exactly. You can rewrite \[\large x^{-\frac{1}{3}}\]
1/x^1/3?
where the 2 ? @bibby ?
The whole thing is multiplied by 2/3 @RadEn
would the derivative be 2/3x^(1/3) ?
correct
yeah , it is 2/3 * x^(-1/3) or 2/(3x^(1/3))
And what type of discontinuity would this function be?
would the function represent an infinite discontinuity?
this is what the graph looks like. I can't tell what kind of discontinuity it'd be http://www.wolframalpha.com/input/?i=2%2F%283x%5E%281%2F3%29%29
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