Question

Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −one half.

f(x) = −(x + 2)2 − three fourths

f(x) = (x + 2)2 + three fourths

f(x) = −(x − 2)2 + three fourths

f(x) = −(x − 2)2 − three fourths

Answer 1

Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.

f(x) = −one fourth x2

f(x) = one fourth x2

f(x) = −4x2

f(x) = 4x2

Answer 2

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = -1.

f(x) = −one twelfth (x − 5)2 + 2

f(x) = one twelfth (x − 5)2 + 2

f(x) = −one twelfth (x + 5)2 + 2

f(x) = one twelfth (x + 5)2 + 2

Answer 3

@amistre64 these are the last question that i need help on

Answer 4

@AngelPSP @DeadShot @allopersonwhat @LilliBelle @nicholasradley @cupcake111 @Jonathan1997 @damien @RyGuy

Answer 5

recall that the directrix and the focus are both equidistant to the vertex


where would that put the vertex of the parabola?

Answer 6

umm i dont really know... im finna guess and say 2