Question

What is the equation of a line that passes through (4,7) and has a slope of -1/4 in point-slope form ?

Answer 1

point slope form is:
\[\large{
y-y_1=m(x-x_1)
}\]

Answer 2

it is y-7=-1/4(x-4)

Answer 3

m is the slope, replace x1 by 4 and y1 by 7

Answer 4

\[y=\frac{ x }{ 4 }+ 8\]

Answer 5

(7)=(-1/4)*(4)+b

Answer 6

no that is not point-slope form

Answer 7

that is the y-intercept form
\[\large{
y=mx+b}\]

Answer 8

thats right @lucaz

Answer 9

here are the choices
\[y=\frac{ x }{ 4 }- \frac{ 7 }{ 4 } ..... y=- \frac{ x }{ 4}+\frac{ 7 }{ 4 }..... y=-\frac{ x }{ 4 }+8.....y=\frac{ x }{ 4 }+8\]

Answer 10

@lucaz

Answer 11

is the third one suppose to be x+8

Answer 12

nope, that's how it was written bro

Answer 13

what are your opinions guys ?

Answer 14

doesnt make sense for me

Answer 15

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ 7}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -\cfrac{1}{4}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \)

Answer 16

my guess was the 3rd one lol

Answer 17

I think its the third one but not certain.
i got something else. sorry
y=-1/4x+8

Answer 18

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ 7}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -\cfrac{1}{4}
\\ \quad \\

y-{\color{blue}{ 7}}={\color{green}{ -\cfrac{1}{4}}}(x-{\color{red}{ 4}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}
\)

distribute the -1/4, see what you get, and solve for

Answer 19

geez, I inverted x and y.. from @jdoe0001 's post you see the answer is
y = -x/4 + 8