The tangent to the curve xy=4 at a point p in the first quadrant meets the x-axis at A and the y-axis at B. Prove that the area of triangle AOB, where O is the origin, is independent of the position P. Really need help with this question!!! D:
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OpenStudy (anonymous):
|dw:1392250066394:dw| I think this is how it would look like but im not sure
OpenStudy (anonymous):
is the area always 1?
OpenStudy (anonymous):
It doesnt say
OpenStudy (anonymous):
No, i mean the area is always 2
well, suppose P = (a,1/a), then the tangent line at x = a is
y = (-1/a^2) (x - a) + 1/a
when x = 0, y = 2/a
when y = 0, x = 2a
A = (1/2) (2/a) (2a) = 2
so it doesn't depends on the coordinate of P
OpenStudy (anonymous):
hmm...doesnt make sense to me, sorry im lost
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OpenStudy (anonymous):
I had y = 1/x when I should have had y = 4/x. But the process is still the same
OpenStudy (anonymous):
|dw:1392251301193:dw|
OpenStudy (anonymous):
A = (1/2) (base ) (height)= (1/2) (2a)(8/a) = 8
OpenStudy (anonymous):
you know how to find the tangent line right?
OpenStudy (anonymous):
oh okay that makes sense thanks
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