The tangent to the curve xy=4 at a point p in the first quadrant meets the x-axis at A and the y-axis at B. Prove that the area of triangle AOB, where O is the origin, is independent of the position P. Really need help with this question!!! D:
|dw:1392250066394:dw| I think this is how it would look like but im not sure
is the area always 1?
It doesnt say
No, i mean the area is always 2 well, suppose P = (a,1/a), then the tangent line at x = a is y = (-1/a^2) (x - a) + 1/a when x = 0, y = 2/a when y = 0, x = 2a A = (1/2) (2/a) (2a) = 2 so it doesn't depends on the coordinate of P
hmm...doesnt make sense to me, sorry im lost
I had y = 1/x when I should have had y = 4/x. But the process is still the same
|dw:1392251301193:dw|
A = (1/2) (base ) (height)= (1/2) (2a)(8/a) = 8
you know how to find the tangent line right?
oh okay that makes sense thanks
|dw:1392252599098:dw|
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