Question

How do you do 1/3<1-2x/3<5/4
Am I suppose to find the LCD?

Answer 1

yes, you can do like this.

Answer 2

Okay, so I got 4<-8x<11 and it has to be in interval notation but the solution says[-11/8,0)

Answer 3

\[\frac{ 1 }{3 }<\frac{ 1-2x }{ 3 }<\frac{ 5 }{4 }\]
multiply by 12
4<4-8x<15
4-4<4-8x-4<15-4
0<-8x<11
\[0> x>\frac{ -11 }{8 }~or~\frac{ -11 }{ 8 }<x<0,x \in \left( \frac{ -11 }{8 },0 \right)\]

Answer 4

Oh, okay. I get it. I didn't subtract 4 by itself. Thanks

Answer 5

yw