Tristan says that solutions to radical equations are extraneous. Hadley says that solutions to radical equations are non-extraneous. Find an equation where Tristan is correct and second equation where Hadley is correct. Using complete sentences, explain each step when solving to justify your examples.

Question

anonymous · Answer

@satellite73

anonymous · Answer

not sure what the question is asking
are you trying to find a radical equation with an extraneous solution?

anonymous · Answer

fiing to equations where there are both right

anonymous · Answer

here is a radical equation 
$$x=\sqrt{2x+3}$$ if you square both sides you get 
$$x^2=2x+3$$ or 
$$x^2-2x-3=0$$ solutions are $3$ and $-1$
$-1$ is extraneous, $3$ is an actual solution

anonymous · Answer

are you going to call me an idiot again @me

mertsj · Answer

Tristan:
$$\sqrt{x-2}=-3$$
$$x-2=9$$
$$x=11$$
Check:
$$\sqrt{11-2}=-3$$
$$\sqrt{9}=-3$$
$$3\neq-3, extraneous$$

mertsj · Answer

Hadley:
$$\sqrt{x-2}=3$$
$$x-2=9$$
$$x=11$$
Check:
$$\sqrt{11-2}=3$$
$$\sqrt{9}=3$$
$$3=3, non-extraneous$$