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please help me find h on this pythagoream problem: h^2=a^2+(a/2)^2 answer a.(a√5)/2 b.a√3 c.a√5 d.(a√3)/2
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\[h^2=a^2+(a/2)^2 = a ^{2}+\frac{ a ^{2} }{ 2^{2} }=a ^{2}+\frac{ a ^{2} }{ 4 }\]Simplify this expression.
ok let me try
is that like a sum of fraction right i just put 1 under a^2
so the result is 5a^2/4
Experiment first: Try adding 1/4 to 1 (or 1 to 1/4). Yes, your result is correct. Congrats!
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but i dont see that result on the options please help me/
The quantity that we calculated was h^2. To find h, merely take the square root of our expression for h^2. Suggest choosing the positive square root.
ok so h=√5a^2/√4
or h=√5a^2/4
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