please help me find h on this pythagoream problem: h^2=a^2+(a/2)^2
answer
a.(a√5)/2
b.a√3
c.a√5
d.(a√3)/2

Question

please help me find h on this pythagoream problem: h^2=a^2+(a/2)^2
answer
a.(a√5)/2
b.a√3
c.a√5
d.(a√3)/2

mathmale · Answer

$$h^2=a^2+(a/2)^2 = a ^{2}+\frac{ a ^{2} }{ 2^{2} }=a ^{2}+\frac{ a ^{2} }{ 4 }$$Simplify this expression.

anonymous · Answer

ok let me try

anonymous · Answer

is that like a sum of fraction right i just put 1 under a^2

anonymous · Answer

so the result is 5a^2/4

mathmale · Answer

Experiment first:

Try adding 1/4 to 1 (or 1 to 1/4).

Yes, your result is correct.  Congrats!

anonymous · Answer

but i dont see that result on the options please help me/

mathmale · Answer

The quantity that we calculated was h^2.  To find h, merely take the square root of our expression for h^2.  Suggest choosing the positive square root.

anonymous · Answer

ok so h=√5a^2/√4

anonymous · Answer

or h=√5a^2/4