Question

What is the factorization of the trinomial below?

4x2 - 20x + 24

Answer 1

hmm maybe this time try it without the steps ^^

do you have problems with the method?

Answer 2

Yes with the A*C because I'm mixed up about which is which

Answer 3

It is:\[ax^2+bx+c\]

Answer 4

A*C?

you have three ways to solve this:
the square method
the cross method i showed earlier
and the general equation method

choose and i'll help^^

Answer 5

the cross method

Answer 6

The a-c method:
1. Find factors of a*c that add up to b-term

Answer 7

sure, hang on a sec

just note though, its a good and fast method, but its harder once the numbers get bigger, and some equations won't be able to be solved by this

Answer 8

then use gcf

Answer 9

try it yourself this time, i'll guide you through!

Answer 10

basically the first column you'll need to find two numbers that when multiplied, get you the thing below, which is 4x^2

so there are two possibilities:
x^2
4x^2

and

2x^2
2x^2

this method is actually a trial and error method, so you'll need practice.

Answer 11

dang i gotta go, message me if anything

Answer 12

\[4x^2-20x+24\]Start by identifying any common factors:
\[4*x^2-4*5x+4*6 = 4(x^2-5x+6)\]We'll set that \(4\) aside until later, and just factor the stuff inside the parentheses.\[x^2-5x+6\]

To factor \(x^2-5x+6\), we need to find a pair of factors of \(6\) that will add up to \(-5\). Clearly, both will have to be negative to give us a positive \(6\) as the product and \(-5\) as the sum. We can factor 6 into two negative factors as follows:
\[-1*-6\]\[
-2*-3\]\[
-3*-2\]\[
-6*-1\]
Clearly, our choice is \(-2, -3\), so our factoring would be\[x^2-5x+6 = (x-2)(x-3)\]Combining that with the common factor of \(4\) we found earlier, \[4x^2-20x+24=4(x-2)(x-3)\]

Let's check our answer:
\[4(x-2)(x-3) = (4x-8)(x-3) = 4x*x - 3*4x -8*x -8(-3) \]\[ =4x^2-12x-8x+24\]\[=4x^2-20x+24\checkmark\]