Question

Locate the saddle point of the function.
f(x,y) = x^(2) − 6x + y − e^(y)

Answer 1

Can you locate all critical points?

Answer 2

You want \(f_x =0\) and \(f_y=0\)

Answer 3

i get confused with e

Answer 4

You can't differentiate it?

Answer 5

\[
\frac{d}{dy}e^y=e^y
\]

Answer 6

so would fy = 1 - ye^(y) ?

Answer 7

No, there shouldn't be a \(y\) in front.

Answer 8

just 1 - e^(y) ?

Answer 9

yes

Answer 10

would fyy = e^(y)

Answer 11

where is the -?

Answer 12

oops -e^(y)

Answer 13

okay so right now i have:
fx = 2x - 6
fy = 1 - e^(y)
fxx = 2
fxy = 0
fyy = -e^(y)