Question

Find dy/dx
cscx^2

Answer 1

\[
\csc^2(x) = \frac{1}{\sin^2(x)}
\]

Answer 2

thanks @wio

Answer 3

Find dy/dx, if cscx^2, is a bit ambiguous; I am unsure of whether you, shrouq, meant the function (csc x)^2 or the (different) function csc (x^2).

If you meant the former, then you could rephrase the question as
Find dy/dx when y=(sin x)^(-2).

Answer 4

\[\frac{ dy }{ dx }=\frac{ d }{ dx }(\sin x)^{-2}=-2(\sin x)^{-3}\frac{ d }{ dx}\sin x\]