Question

Can someone help me solve these and explain the steps to me
1. 2/(x+3) - 1/x = -6/x(x+3)
2. 1/2 + x/6 = 18/x

Answer 1

@radar @satellite73

Answer 2

Let's do problem 1 first. We need to get rid of the fractions. Do you know how we would do that?

Answer 3

No :( don't we need to find the LCD? @nelsonjedi

Answer 4

Yes....so waht is the LCD?

Answer 5

x +3?

Answer 6

Will x+3 go into x?

Answer 7

huh?

Answer 8

The LCD is the lowest factor of the numbers. Thus x(x+3) is the LCD.

Answer 9

ooh okay so now that we determine x(x+3) as the LCD what do we do?
I got this is this right?
2x/x(x+3) - 1(x+3)/x(x+3) = -6/x(x+3)

Answer 10

You multiply each number by the LCD. So let's do 2 / (x+3) if I multiply it by x(x+3) what do I get?

Answer 11

why would you multiply by the whole LCD, don't you just want to get the denominator equal to the LCD?

Answer 12

No we want to get rid of the denominator when solving fractions. So what is 2/(x+3) * x (x+3) =?

Answer 13

2x(x+3)/x^2 + 6x + 9

Answer 14

\[\frac{ 2 }{ (x+3) } X \frac{ x(x+3) }{ 1 }\]

Answer 15

This is how the equation would look. so we would end up with 2 * x * (x+3) / (x+3)...Correct?

Answer 16

yess

Answer 17

The (x+3) cancels each other out so we end up with what?

Answer 18

2x!

Answer 19

Bingo. Now can you do the second one for 1/x?

Answer 20

no 2x^2

Answer 21

ooh nvm lol wouldn't you get just x?

Answer 22

sorry for 1/x wouldn't you get x?

Answer 23

Multiply the top by the LCD

Answer 24

Ohh you would get (x+3)

Answer 25

Correct. So what would it be for 6/(x)(x+3) ?

Answer 26

you would get 6 because everything would cancel out right?

Answer 27

I don't get what to do with 2x - x+3 = 6 ?

Answer 28

I don't get what to do with 2x - x+3 = 6 ?

Answer 29

Just maybe there are no solution to these!

Answer 30

@radar I know there is no answer to the first one but the second one of -12, 9 I got the answers from thee back of my book, but I just want to know how to solve them :/