Determine magnitude of earthquake half as intense as an 8.0 magnitude earthquake?
Please! I have a math midterm tomorrow (:
Sorry, I'm googling around for the Richter formula. I know it's a logarithmic function, but I don't remember exactly what it is. Do you have it handy?
This is all I have: A = Ao x 10^R
Or: M= logA / Ao
Try log((10^8)/2) ?
That seems about right. 7.69897
intensity=function of magnitude whats the formula
or mag=Function of (intensity) you need formula of that
Thanks guys!! Tom Hue you're a lifesaver! I'm pretty sure that's it too
Yup. 8.0 is ten times more powerful than 7.0, so somewhere in between is about right. I think the whole A0 thing is some form of distance from the epicenter where I guess 1 would be directly at it. The formula would simply be magnitude=log(amplitude), or 10^magnitude=amplitude. M=8, so 10^8=A. Half that is (10^8)/2, plug it into the logarithmic, you get ~7.7.
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