Question

(1+sinx/cosx)+(cosx/1+sinx)=2/cosx Prove identity

Answer 1

did you try cross-multiplying ?
like,
\(\Large \dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+cb}{bd}\)

Answer 2

if you tried that, then what would you get on the left side ?

Answer 3

(1+sinx)(1+sinx)+cosx.cosx/[cosx.(1+sinx)]
[(1+sinx)^2+cos^2x]/cosx.(1+sinx)
1+sin^2x +2sinx+cos^2x /cosx(1+sinx)
1+1+2sinx/cosx(1+sinx)
2+2sinx/cosx(1+sinx)
taking 2 as common and cancelling 1+sinx
2(1+sinx)/cosx(1+sinx)
=2/cosx