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evaluate the integral (√(1/x)-2) dx from 1 to 4
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is the -2 in the square root or not ?
it is not
sorry, i have to go now. let me tag my best friends :) @ganeshie8 , @whpalmer4
So is that\[\int_1^4 (\sqrt{\frac{1}{x}} -2) dx\]
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yes
Well, we can split this into two integrals: \[\int_1^4 \sqrt{\frac{1}{x}}\,dx - \int_1^4 2\,dx \]right? Can you tell me the result for the right-hand integral?
The left hand integral you can rewrite if you recall that \[\large \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}\]and \[\large \sqrt{x} = x^{\frac{1}{2}}\]
That gives you an expression to which you can apply the power rule for integration.
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