Question

how many grams of copper metal are present in a 4.25g sample of copper(II) fluoride dihydrate?

Answer 1

Welcome to Open Study!
Steps:
1. From the mass of copper you can find moles by deviding the mass by molar mass (mola mass is just the adding up of the masses of each atom in one mole and can be found on the periodic table \(n=\dfrac{m}{M}\).
2. Use mole ratio! How many coppers are in copper (II) flouride dihydrate? There are 2 so \(\ nCu = n compund * 2\) First of all do you know how to write the chemical formula for this compound?
3. Now you find mass of Cu by re-arranging the eqn in 1.

Answer 2

Okay, so this is just a stoichiometry problem. First, you have to convert the grams of copper to moles in the equation of CuF2.

Answer 3

So take 4.25g Cu * 1 mol Cu / 63.54g Cu then go to the next step.

Answer 4

Since there are 2 moles of Flourine and 1 mole of copper, you set the equation like this.0668 mol Cu * 2 mol F / 1 mol Cu

Answer 5

You then take that answer, multiply is by the grams of one mole of copper (look on the periodic table under copper for the mass) and then divide that by one mol. That is your answer.

Answer 6

Oh whoops, by bad. I thought I saw that the 4.25g was the mass of the copper. @AnImEfReaK is right.