Geometry: Coordinate Applications I've been working on this problem for days now without being able to get a right answer, so any guidance/help would be very very appreciated. "Point P is located at (-2,7) and point R is located at (1,0). Find the point Q that is located 2/3 the distance from point P to point R." What the lesson/teachers have been teaching is to first count the difference in x value between point (which, x =3) and then the y value (y = 7). Then using those points, multiply each one by 2/3 distance. X: 2/3 times 3/1 = 6/3 = 2 Y: 2/3 times 7/1 = 14/3
After that point, I'm extremely confused. Blah.
So first and foremost, always always draw a picture
it helps you in every math class for the rest of your life
I've actually got a picture drawn in my notebook that I've been working on the problem in.
you are almost done. you start at (-2,7) and add (2, 14/3) to get to pt Q
So would I turn 14/3 into a mixed number or how would that work, in order to be graphed?
yes, it's easiest to turn 14/3 into a mixed number 4 ⅔ before adding to 7.
This is probably (definitely) wrong, but adding the two I ended up with (0,12 2/3) :|
good good, so if you draw that here, we can go from that if you like
7+4 is 11 not 12
11 2/3, in that case lol :p.
and that is definitely correct
My options for the question are: (-1.3, 4.9) (-1, 4.7) (-0.3, 2.5) (0, 2.3) I'm so confused lolol
oh, wait.... we want to go down 4 ⅔ from 7 (not up)
Ohhh. In that case... (0, 2 1/3)?
yes, 2 ⅓ is 2.3333 which they apparently rounded to 2.3
So (0, 2.3) it is!
I hope the idea is not confusing. If you start at -2,7 and go to 1,0 we go over (to the right) 3 and down 7 if we go partway over (for example ⅔) then we go over ⅔ of 3 and down ⅔ of 7
Oh that makes a lot more sense, actually. I'll go ahead and try the rest of this assignment and see if I'm able to work through them. If not, I'll pop back on here and see where I'm going wrong. I really appreciate your help, it makes a lot more sense now :)
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