Angle C is an inscribed angle of circle P. Angle C measures (20x – 5)° and arc AB measures (30x + 30)°. Find the measure of arc AB.
|dw:1393713680112:dw| \(\bf \textit{incribed angle}=\cfrac{\textit{intercepted arc}}{2}\implies 2\textit{incribed angle}=\textit{intercepted arc}\)
so I put 30x+30 over 2 ? then solve it from there
yes, you can do it that way
I keep getting 18 and I know that isn't the answer im very confused
\(\bf \textit{incribed angle}=\cfrac{\textit{intercepted arc}}{2}\implies 2\textit{incribed angle}=\textit{intercepted arc} \\ \quad \\ 20x-5=\cfrac{30x+30}{2}\implies 40x-10=30x+30\implies 10x=40 \\ \quad \\ x=4\)
does that give you 18?
I kind of get it now but when I do it myself its doesn't come out the way you do
2(20x-5) distributing the 2, will give you 40x-10
oh ok I get it now thank you so much I appreciate your help
yw
Point C is the center of the circle. If angle ACB measures 4 x plus 12 degrees and AB measures x plus 13 degrees, find x. http://curriculum.kcdistancelearning.com/courses/ALG2x-CR-A09/b/assessments/G-GeometryUnitExam/A2CR_Unit7_Exam_LT_118q3.gif
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