Consider the reaction when aqueous solutions of potassium nitrate and chromium(II) iodide are combined. The net ionic equation for this reaction is:
really need help
can you predict the products?
i got 2NO3^- +Cr^2+ > Cr^2+ 2NO3^-
hm is \(Cr(NO_3)_2\) soluble?
it is
so there is no reaction. potassium nitrate + chromium(II) iodide -> N.R.
so i would submit black
blank
i would write "no reaction"
okay so for this one Consider the reaction when aqueous solutions of iron(III) acetate and chromium(III) sulfate are combined. The net ionic equation for this reaction is:
my final answer is 2Fe^3+ + Cr^3+ > Fe^3+ + 2Cr^3+
nope, you wont ever have 2 metals as net products (ions are always soluble in water).
how is there water in this reaction, i dont understand
all of these reactions are occurring in a solution where water is the solvent
acetate is soluble and so is sulfate that is all crossed out right
it's kind of a tricky question because \(FeSO_4\), where \(Fe^{2+}\), is soluble but \(Fe_2(SO_4)_3\), where \(Fe^{3+}\), is not.
oh okay so i dont separate those?
nope that would be a precipitate.
and Cr2(SO4)3 would precipitate too right
when you mix it in water (in the solution) it will break apart into \(Cr^{3+}\) and sulfate ions, so you can assume that it's soluble.
okay so theres no reactions since everything separated is soluble
the reaction is between \(Fe^3+\) and \(SO^{2-}_2\)
my answer is Fe^3+ + SO4^2- >Fe2(SO4)3
yup
really wow thank you
are they aqueous state
on the left side, yes. on the right it's a precipitate, so solid.
its not 2Fe^3+ on the left?
oh yes, sorry i didn't even check for that, it should be 2Fe^3+ + 3SO4^2- >Fe2(SO4)3
it was wrong
aaronq!!!?
oh really? i'm sorry, i'm pretty sure it's insoluble though :S
thank you abb0t thats is really helpful
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