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To produce 2.51 liters of a 1.55 M solution of magnesium nitrate, how many grams of magnesium nitrate must be dissolved?
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@aaronq
there are a few ways to do this, i like substitution: \(n=\dfrac{m}{Molar~mass}\) into the molarity formula \(M=\dfrac{n_{solute}}{L_{solution}}\) \(M=\dfrac{\dfrac{m}{Molar~mass}}{L_{solution}} \rightarrow M=\dfrac{m}{L_{solution}*Molar~mass}\)
plug in all the values (molarity, L, and Molar mass) then solve for mass, m.
thanks:)
no problem !
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