find the linear function f(x) for which both f(-2) and f(0)=-4
If you have a linear function that has 2 x values produce the same y value, then this function must graph a horizontal line.
it's f(-2)=6, sorry
oh nvm
are you able to find the slope through the two points (-2,6) and (0,-4) ?
How do I come up with that?
are you familiar with the slope formula?
It's y=mx+b right?
that's slope intercept form, which is close to what I'm referring to
I'm actually talking about this formula \[\Large m = \frac{y_2-y_1}{x_2-x_1}\]
I don't know which one to plug which into. I think that's my problem.
Basically you find the y difference by subtracting the y coordinates Do the same for the x coordinates (in the same order) then you divide the y difference by the x difference
(x1,y1) is your first point (x2,y2) is the second
In this case (x1,y1) = (-2,6) (x2,y2) = (0,-4)
So it would look like -4-6 over 0-2?
very close, but it should be -4-6 over 0 - (-2)
So the slope would be -5/1 ?
which reduces to -5
the slope is m = -5 the y-intercept is b = -4 ... this is because f(0) = -4
plug m = -5 and b = -4 into y = mx + b to get y = mx + b y = -5x + (-4) y = -5x - 4
Therefore, the linear function is f(x) = -5x - 4
Awesome. I think I get it now.
That's great that you do
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