Question

Solve these two equations :
2sin^2 x - 5sin x - 3 = 0
(cos x - (square root of 2)/2)(sec x - 1) = 0

Answer 1

@sourwing

Answer 2

@inkyvoyd

Answer 3

@aelong

Answer 4

is someone online?

Answer 5

Hello QuenBee - wow Open Study is acting so nutty it took me a few minutes just to click in here.

Answer 6

Let's sue OS XDD

Answer 7

haha ok could you guys help me out with those two questions please?

Answer 8

I think I have solved the first equation x = 330°

Answer 9

lol! can you explain?

Answer 10

sorry last time I gave an answer like that to my teacher (x= so and so) and nothing else she laughed at my face and told me to do the assignment again

Answer 11

Well, sorry for giving an answer.
I guess you want to see the work too huh?

Answer 12

so far I have sin x = -1/2 and sin x = 3?

Answer 13

no, no you misunderstood I meant thanks but an explanation would be great

Answer 14

so could you show the steps on how u got there?

Answer 15

2sin^2 x - 5sin x - 3 = 0
Actually, I programmed the equation into an electronic spread sheet and found it by trial and error.

Answer 16

oh

Answer 17

I imagine the equation has to be manipulated algebraically, etc?

Answer 18

yes

Answer 19

I have (2sin x + 1)(sin x -3) = 0

Answer 20

2 sin² (x) -6sin(x) +sin(x) -3 =0
THat seems to be factored correctly.

Answer 21

2 sin^2(x) - 6sin(x) - 3 is the one that's correct

Answer 22

?

Answer 23

No, I just multiplied the factoring that you got. Basically, I'm saying you are right.

Answer 24

Multiplying
(2sin x + 1)(sin x -3)
equals
2 sin² (x) -6sin(x) +sin(x) -3 =0

Answer 25

so for x I get sin^-1(-1/2) and 3 is that correct?

Answer 26

sin^-1 (-1/2) would be pi/6?

Answer 27

hey u there?

Answer 28

hello??