Question

what is the value of 3x2y3c when x=3 y=-2 and c= 1/3?

Answer 1

3*(3^2)*(-2^3)*(1/3)

Answer 2

Solution..
\[(3x^{2})(y ^{3})c\]
\[(3(3)^{2})(-2^{2})(1/3)\]\[(3(9))(4)(1/3)\]\[(27)(4)(1/3)\]\[108/3\]\[36\]
This is the answer...