1)A satellite in a circular orbit 700 miles above the surface of the Earth. What is the period of the orbit?

You may use the following constants:

Radius of the Earth: 4000 miles
Gravitational Constant: 6.67×10^−11m3/(kg⋅s2)
Mass of earth: 5.98×10^24kg
Number of Meters in a mile: 1609

Period = seconds
help please i tried this question a few times but cant get it right i use w=sqrt(GM)/R^(3/2)

Question

1)A satellite in a circular orbit 700 miles above the surface of the Earth. What is the period of the orbit? 

You may use the following constants: 

Radius of the Earth: 4000 miles 
Gravitational Constant: 6.67×10^−11m3/(kg⋅s2) 
Mass of earth: 5.98×10^24kg 
Number of Meters in a mile: 1609 

Period =                  seconds
help please i tried this question a few times but cant get it right  i use w=sqrt(GM)/R^(3/2)

jack1 · Answer

period = time for one complete osciliation
si first question: is it geostationary? if so...24 hrs...?
so period in seconds is
$$\frac {24~hrs}{1} \times \frac {60~mins}{1~hr} \times \frac {60~sec}{1~min} = x~sec$$
so 24  x  60  x   60 = number of seconds