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Help Please<3 If an object is dropped from a height of 200 feet, the function h(t)=-16t^2+200 gives the height of the object after t seconds. Approximately, when will the object hit the ground? A. 200.00 sec B. 184.00 Sec C. 3.54 D. 0.78 sec
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when object hit the ground then its height should be =f(t)=0
sorry h(t)=0
Thanks So Much Guys, R U Sure?:)<3 so it would be D?
so 0=-16t^2+200 16t^2=200 t^2=200/16 t=root(200/16)=10*root(2)/4
Humm thats confusing
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This is embarrassing>.< i hate math i can never get it:(
okkk
0=-16t^2+200
16t^2=200
u got till here ??? @Monica75
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yes
t^2=200/16 t=root(200/16)
t=root(200/16)=3.535=3.54 sec
now ???
@Monica75
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OHHH i see !its all simple steps, thanks for showing me! and taking your time out to help
wlcme :)
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