Medals!!! Need more help...kindergarten children have normally distributed heights with a mean of 39 inches and a standard deviation of 2 inches. what is the probability that a randomly chosen kindergarten child will have a height between 37 and 41 inches?
well, since they are both 1 deviation from the mean ...
what does the empirical rule tell us?
more hints : 68-95-99.7
about 68% lies within 1 SD
of the mean
+- 1 sd of the mean tha tis
since 39 + 1sd = 41 and 39 - 1sd = 37 we are +-1 sd of the mean
\[P\left( 37 < X < 41 \right)=\]\[P\left( \frac{37-39}{2} < \frac{X-39}{2} < \frac{41-39}{2} \right)=P\left( -1 < Z < 1 \right)=\]
0.6826
I really have no idea what I am doing
do you know how to find the area underneath a curve?
i see it in my book and try to work it out however i never end up getting the right answers. i have gone to almost every website.
this is my last assignment for class, thankfully.
the tables in a book are the calculations tha tpeople made a long time ago so that they would not have to do the calculus everytime they wanted to determine a value. instead of repeating the same thing over and over again, they just listed the values of greatest importance and looked it up when they needed it
a normal curve is one that is high in the middle and skinny at the ends ... visually|dw:1394293850167:dw| the total area under the curve is equal to 1, the area between any interval is equal to the probability of being in that interval
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